Mathematical entropy, vanishing viscosity, and symmetrizability. This note explains the relationship between symmetric hyperbolic form and the existence of an entropy. It + defines mathematical entropy, + shows that viscosity solution satisfies the entropy inequality, and + shows that symmetrizability of a hyperbolic system implies the existence of a mathematical entropy. Below xi:=x^i, fi:=f^i, and ri:=r^i, and the repeated index i indicates summation from 1 to 3. We study the conservation law u_t + fi_xi = 0. === Entropy Framework === To seek an entropy phi, we multiply and dot the quasilinear form with phi_u: phi_u.u_t + phi_u.fi_u.u_xi = 0. Suppose that we can find phi(u) and Fi(u) such that Fi_u = phi_u.fi_u. Then entropy is conserved: phi_t + Fi_xi = 0. Observation: in an adiabatic system the value of the "entropy" s=log(p\rho^{-\gamma}) is conserved along particle paths: d_t(s) = 0. This means that phi:=(\rho s) is entropy in the sense above of having an entropy flux: (\rho s)_t + \Div(\u \rho s) = 0. If we also assume that phi_uu is positive definite, we can show that phi_t + Fi_xi <= 0 (in the sense of distributions), and that this picks out the vanishing viscosity solution. To see this, we consider the viscosity solution u_t + fi_xi = \epsilon u_{xi,xi} and assume that, as \epsilon goes to zero, u converges uniformly to a vanishing viscosity solution. As before, we convert the viscosity solution to a (viscous) entropy evolution equation by taking the dot product with phi_u: phi_t + Fi_xi = \epsilon \phi_u.u_{xi,xi} Looking for a "chain rule" to simplify the RHS (or looking for a product rule to move derivatives from u) prompts the observation phi_xi = phi_u.u_xi and phi_{xi,xi} = (phi_uu.u_xi).u_xi + phi_u.u_{xi,xi}, so the entropy evolution equation becomes phi_t + Fi_xi = \epsilon (phi_{xi,xi} - (phi_uu.u_xi).u_xi). Invoking that phi_uu is positive definite, (phi_uu.u_xi).u_xi >= 0, so we get the viscous entropy evolution inequality phi_t + Fi_xi - \epsilon phi_{xi,xi} <= 0. Roughly, taking \epsilon -> 0 gives phi_t + Fi_xi <= 0. More rigorously, to show that this holds in the sense of distributions, we multiply the viscous entropy inequality by a test function v and integrate (by parts) over time T=[0,\infty), and the spatial domain X: \int_T \int_X (u v_t + fi v_xi + \epsilon u v_{xi,xi}) >= 0. Assuming that u is uniformly bounded and converges as \epsilon goes to zero, the dominated convergence theorem allows us to bring the limit inside the integral and gives \int_T \int_X (u v_t + fi v_xi) >= 0, which is what is meant by the statement phi_t + Fi_xi <= 0 (in the sense of distributions). === symmetric variables framework === Given the conservation law u_t + fi_xi = 0, we seek symmetric variables v. The chain rule says that u_v.v_t + fi_v.v_xi = 0. Suppose that u_v and fi_v are symmetric. Then by Green's theorem path integrals are independent of (rectilinear) path and can be used to define scalar potentials q and ri satisfying u = q_v and fi = ri_v, where we note that q is convex if u_v is positive definite; in this case u(v) is injective and we can speak of v(u). The Legendre transform (which is convexity-preserving), phi(u) = u.v - q(v), and the "generalized Legendre transform" (?), Fi(u) = fi.v - ri(v), then allow us to write v = phi_u, where phi_uu is positive definite, and Fi_u = v.fi_u = phi_u.fi_u, which satisfies the conditions in the entropy framework to conclude that phi_t + Fi_xi <= 0, as needed. We remark that the entropy is the Legendre transform of the potential of the state with respect to the symmetric variables. (In other words, the derivative of the entropy is the inverse of the derivative of the potential function of the state variables.) Similarly, the entropy fluxes are the "generalized Legendre transform" of the potential of the fluxes with respect to the symmetric variables.